Hi I'm wondering whether using hasIntersection between a list and a map works? Will the items of a list be compared with the keys of a map?

Hi Kevin, No, it takes only lists, but you can convert a map to a list of keys using the

map

function:

hasIntersection(["a", "b"], {"a":1}.map(x, x))

thanks I just found that your method worked!

You can run

cerbos repl

to get the Cerbos REPL.

looks like filter also converts map to list

Yes. I think all built-in CEL functions do that. I wanted to double-check that, but GitHub is down!

hasIntersection

is a custom Cerbos function. CEL is a language (developed by Google) that Cerbos uses in the policies.

Hi, what does hasIntersection return when comparing empty sets?

Yes, it returns false in that case.

thanks